How To Create A Table With A Two Or More Foreign Keys Using Android Room?

According the entity-relationship model, the relationship between tbl_post and tbl_category could be specified using Room Persistency Library as follows: @Entity(foreignKeys = @Fo

Solution 1:

TblCategory.java

@Entity
class TblCategory {
    @PrimaryKey@ColumnInfo(name="cat_id")
    public String id;

    @ColumnInfo(name = "cat_name")
    public String name;
}

TblPost.java (It is missing the foreign key reference but it is not important for the case)

@Entity
class TblPost {
    @PrimaryKey@ColumnInfo(name="post_id")
    public String id;

    publicStringtitle, content, create_time, author_id;
}

TblPostCategory.java

@Entity(foreignKeys = {
    @ForeignKey(
        entity = TblPost.class,
        parentColumns = "post_id",
        childColumns = "tbl_post_id"
    ),
    @ForeignKey(
        entity = TblCategory.class,
        parentColumns = "cat_id",
        childColumns = "tbl_category_id"
    )
})
class TblPostCategory {
    @PrimaryKey@ColumnInfo(name="tbl_post_id")
    public String id;

    @ColumnInfo(name = "tbl_category_id")
    public String categoryId;
}

Solution 2:

In Kotlin:

@Entity(
    tableName = "some_table",
    indices = [Index("id"), Index("brand_id"), Index("model_id")],
    foreignKeys = [
        ForeignKey(entity = BrandEntity::class, parentColumns = ["id"],
            childColumns = ["brand_id"]),
        ForeignKey(entity = ModelEntity::class, parentColumns = ["id"],
            childColumns = ["model_id"]),
        ForeignKey(entity = Table1Entity::class, parentColumns = ["id"],
            childColumns = ["table1_id"]),
        ForeignKey(entity = Table2Entity::class, parentColumns = ["id"],
            childColumns = ["table2_id"])
    ]
)